3.638 \(\int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} (A+C \cos ^2(c+d x)) \, dx\)

Optimal. Leaf size=523 \[ \frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{1287 b^3 d}-\frac {4 a \left (24 a^2 C+143 A b^2+166 b^2 C\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{9009 b^3 d}+\frac {4 a \left (a^2-b^2\right ) \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} F\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{45045 b^4 d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (240 a^4 C+10 a^2 b^2 (143 A+124 C)-539 b^4 (13 A+11 C)\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{45045 b^3 d}-\frac {4 a \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{45045 b^3 d}-\frac {2 \left (240 a^6 C+10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)-1617 b^6 (13 A+11 C)\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{45045 b^4 d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\frac {12 a C \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{143 b^2 d}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2}}{13 b d} \]

[Out]

-2/45045*(240*a^4*C-539*b^4*(13*A+11*C)+10*a^2*b^2*(143*A+124*C))*(a+b*cos(d*x+c))^(3/2)*sin(d*x+c)/b^3/d-4/90
09*a*(143*A*b^2+24*C*a^2+166*C*b^2)*(a+b*cos(d*x+c))^(5/2)*sin(d*x+c)/b^3/d+2/1287*(24*a^2*C+11*b^2*(13*A+11*C
))*(a+b*cos(d*x+c))^(7/2)*sin(d*x+c)/b^3/d-12/143*a*C*cos(d*x+c)*(a+b*cos(d*x+c))^(7/2)*sin(d*x+c)/b^2/d+2/13*
C*cos(d*x+c)^2*(a+b*cos(d*x+c))^(7/2)*sin(d*x+c)/b/d-4/45045*a*(120*a^4*C+5*a^2*b^2*(143*A+94*C)-3*b^4*(2717*A
+2174*C))*sin(d*x+c)*(a+b*cos(d*x+c))^(1/2)/b^3/d-2/45045*(240*a^6*C-1617*b^6*(13*A+11*C)+10*a^4*b^2*(143*A+76
*C)-3*a^2*b^4*(13299*A+10223*C))*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticE(sin(1/2*d*x+1/2*c),
2^(1/2)*(b/(a+b))^(1/2))*(a+b*cos(d*x+c))^(1/2)/b^4/d/((a+b*cos(d*x+c))/(a+b))^(1/2)+4/45045*a*(a^2-b^2)*(120*
a^4*C+5*a^2*b^2*(143*A+94*C)-3*b^4*(2717*A+2174*C))*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticF(
sin(1/2*d*x+1/2*c),2^(1/2)*(b/(a+b))^(1/2))*((a+b*cos(d*x+c))/(a+b))^(1/2)/b^4/d/(a+b*cos(d*x+c))^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 1.28, antiderivative size = 523, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.257, Rules used = {3050, 3049, 3023, 2753, 2752, 2663, 2661, 2655, 2653} \[ \frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) \sin (c+d x) (a+b \cos (c+d x))^{7/2}}{1287 b^3 d}-\frac {4 a \left (24 a^2 C+143 A b^2+166 b^2 C\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{9009 b^3 d}-\frac {2 \left (10 a^2 b^2 (143 A+124 C)+240 a^4 C-539 b^4 (13 A+11 C)\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{45045 b^3 d}-\frac {4 a \left (5 a^2 b^2 (143 A+94 C)+120 a^4 C-3 b^4 (2717 A+2174 C)\right ) \sin (c+d x) \sqrt {a+b \cos (c+d x)}}{45045 b^3 d}+\frac {4 a \left (a^2-b^2\right ) \left (5 a^2 b^2 (143 A+94 C)+120 a^4 C-3 b^4 (2717 A+2174 C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} F\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{45045 b^4 d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)+240 a^6 C-1617 b^6 (13 A+11 C)\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{45045 b^4 d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\frac {12 a C \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{7/2}}{143 b^2 d}+\frac {2 C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2}}{13 b d} \]

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(5/2)*(A + C*Cos[c + d*x]^2),x]

[Out]

(-2*(240*a^6*C - 1617*b^6*(13*A + 11*C) + 10*a^4*b^2*(143*A + 76*C) - 3*a^2*b^4*(13299*A + 10223*C))*Sqrt[a +
b*Cos[c + d*x]]*EllipticE[(c + d*x)/2, (2*b)/(a + b)])/(45045*b^4*d*Sqrt[(a + b*Cos[c + d*x])/(a + b)]) + (4*a
*(a^2 - b^2)*(120*a^4*C + 5*a^2*b^2*(143*A + 94*C) - 3*b^4*(2717*A + 2174*C))*Sqrt[(a + b*Cos[c + d*x])/(a + b
)]*EllipticF[(c + d*x)/2, (2*b)/(a + b)])/(45045*b^4*d*Sqrt[a + b*Cos[c + d*x]]) - (4*a*(120*a^4*C + 5*a^2*b^2
*(143*A + 94*C) - 3*b^4*(2717*A + 2174*C))*Sqrt[a + b*Cos[c + d*x]]*Sin[c + d*x])/(45045*b^3*d) - (2*(240*a^4*
C - 539*b^4*(13*A + 11*C) + 10*a^2*b^2*(143*A + 124*C))*(a + b*Cos[c + d*x])^(3/2)*Sin[c + d*x])/(45045*b^3*d)
- (4*a*(143*A*b^2 + 24*a^2*C + 166*b^2*C)*(a + b*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(9009*b^3*d) + (2*(24*a^2*
C + 11*b^2*(13*A + 11*C))*(a + b*Cos[c + d*x])^(7/2)*Sin[c + d*x])/(1287*b^3*d) - (12*a*C*Cos[c + d*x]*(a + b*
Cos[c + d*x])^(7/2)*Sin[c + d*x])/(143*b^2*d) + (2*C*Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(7/2)*Sin[c + d*x])/(
13*b*d)

Rule 2653

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*Sqrt[a + b]*EllipticE[(1*(c - Pi/2 + d*x)
)/2, (2*b)/(a + b)])/d, x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rule 2655

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[a + b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c +
d*x])/(a + b)], Int[Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 -
b^2, 0] &&  !GtQ[a + b, 0]

Rule 2661

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticF[(1*(c - Pi/2 + d*x))/2, (2*b)
/(a + b)])/(d*Sqrt[a + b]), x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rule 2663

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[(a + b*Sin[c + d*x])/(a + b)]/Sqrt[a
+ b*Sin[c + d*x]], Int[1/Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a
^2 - b^2, 0] &&  !GtQ[a + b, 0]

Rule 2752

Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[(b*c
- a*d)/b, Int[1/Sqrt[a + b*Sin[e + f*x]], x], x] + Dist[d/b, Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a
, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]

Rule 2753

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> -Simp[(d
*Cos[e + f*x]*(a + b*Sin[e + f*x])^m)/(f*(m + 1)), x] + Dist[1/(m + 1), Int[(a + b*Sin[e + f*x])^(m - 1)*Simp[
b*d*m + a*c*(m + 1) + (a*d*m + b*c*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*
c - a*d, 0] && NeQ[a^2 - b^2, 0] && GtQ[m, 0] && IntegerQ[2*m]

Rule 3023

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (
f_.)*(x_)]^2), x_Symbol] :> -Simp[(C*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m + 1))/(b*f*(m + 2)), x] + Dist[1/(b*
(m + 2)), Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m + 2) - a*C)*Sin[e + f*x], x], x]
, x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] &&  !LtQ[m, -1]

Rule 3049

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (B_.)
*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> -Simp[(C*Cos[e + f*x]*(a + b*Sin[e +
f*x])^m*(c + d*Sin[e + f*x])^(n + 1))/(d*f*(m + n + 2)), x] + Dist[1/(d*(m + n + 2)), Int[(a + b*Sin[e + f*x]
)^(m - 1)*(c + d*Sin[e + f*x])^n*Simp[a*A*d*(m + n + 2) + C*(b*c*m + a*d*(n + 1)) + (d*(A*b + a*B)*(m + n + 2)
- C*(a*c - b*d*(m + n + 1)))*Sin[e + f*x] + (C*(a*d*m - b*c*(m + 1)) + b*B*d*(m + n + 2))*Sin[e + f*x]^2, x],
x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2
, 0] && GtQ[m, 0] &&  !(IGtQ[n, 0] && ( !IntegerQ[m] || (EqQ[a, 0] && NeQ[c, 0])))

Rule 3050

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (C_.)
*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> -Simp[(C*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*(c + d*Sin[e + f*x])^(n
+ 1))/(d*f*(m + n + 2)), x] + Dist[1/(d*(m + n + 2)), Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])^n
*Simp[a*A*d*(m + n + 2) + C*(b*c*m + a*d*(n + 1)) + (A*b*d*(m + n + 2) - C*(a*c - b*d*(m + n + 1)))*Sin[e + f*
x] + C*(a*d*m - b*c*(m + 1))*Sin[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, C, n}, x] && NeQ[b*c -
a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 0] &&  !(IGtQ[n, 0] && ( !IntegerQ[m] || (EqQ[a, 0
] && NeQ[c, 0])))

Rubi steps

\begin {align*} \int \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx &=\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {2 \int \cos (c+d x) (a+b \cos (c+d x))^{5/2} \left (2 a C+\frac {1}{2} b (13 A+11 C) \cos (c+d x)-3 a C \cos ^2(c+d x)\right ) \, dx}{13 b}\\ &=-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {4 \int (a+b \cos (c+d x))^{5/2} \left (-3 a^2 C-\frac {5}{2} a b C \cos (c+d x)+\frac {1}{4} \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) \cos ^2(c+d x)\right ) \, dx}{143 b^2}\\ &=\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {8 \int (a+b \cos (c+d x))^{5/2} \left (\frac {1}{8} b \left (1001 A b^2+60 a^2 C+847 b^2 C\right )-\frac {1}{4} a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) \cos (c+d x)\right ) \, dx}{1287 b^3}\\ &=-\frac {4 a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9009 b^3 d}+\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {16 \int (a+b \cos (c+d x))^{3/2} \left (\frac {3}{16} a b \left (1859 A b^2+60 a^2 C+1423 b^2 C\right )-\frac {1}{16} \left (240 a^4 C-539 b^4 (13 A+11 C)+10 a^2 b^2 (143 A+124 C)\right ) \cos (c+d x)\right ) \, dx}{9009 b^3}\\ &=-\frac {2 \left (240 a^4 C-539 b^4 (13 A+11 C)+10 a^2 b^2 (143 A+124 C)\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{45045 b^3 d}-\frac {4 a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9009 b^3 d}+\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {32 \int \sqrt {a+b \cos (c+d x)} \left (\frac {3}{32} b \left (60 a^4 C+539 b^4 (13 A+11 C)+5 a^2 b^2 (1573 A+1175 C)\right )-\frac {3}{16} a \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \cos (c+d x)\right ) \, dx}{45045 b^3}\\ &=-\frac {4 a \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{45045 b^3 d}-\frac {2 \left (240 a^4 C-539 b^4 (13 A+11 C)+10 a^2 b^2 (143 A+124 C)\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{45045 b^3 d}-\frac {4 a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9009 b^3 d}+\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {64 \int \frac {-\frac {3}{64} a b \left (60 a^4 C-5 a^2 b^2 (4433 A+3337 C)-3 b^4 (12441 A+10277 C)\right )-\frac {3}{64} \left (240 a^6 C-1617 b^6 (13 A+11 C)+10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)\right ) \cos (c+d x)}{\sqrt {a+b \cos (c+d x)}} \, dx}{135135 b^3}\\ &=-\frac {4 a \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{45045 b^3 d}-\frac {2 \left (240 a^4 C-539 b^4 (13 A+11 C)+10 a^2 b^2 (143 A+124 C)\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{45045 b^3 d}-\frac {4 a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9009 b^3 d}+\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}+\frac {\left (2 a \left (a^2-b^2\right ) \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right )\right ) \int \frac {1}{\sqrt {a+b \cos (c+d x)}} \, dx}{45045 b^4}-\frac {\left (240 a^6 C-1617 b^6 (13 A+11 C)+10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)\right ) \int \sqrt {a+b \cos (c+d x)} \, dx}{45045 b^4}\\ &=-\frac {4 a \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{45045 b^3 d}-\frac {2 \left (240 a^4 C-539 b^4 (13 A+11 C)+10 a^2 b^2 (143 A+124 C)\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{45045 b^3 d}-\frac {4 a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9009 b^3 d}+\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}-\frac {\left (\left (240 a^6 C-1617 b^6 (13 A+11 C)+10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)\right ) \sqrt {a+b \cos (c+d x)}\right ) \int \sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}} \, dx}{45045 b^4 \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}+\frac {\left (2 a \left (a^2-b^2\right ) \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}}\right ) \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}} \, dx}{45045 b^4 \sqrt {a+b \cos (c+d x)}}\\ &=-\frac {2 \left (240 a^6 C-1617 b^6 (13 A+11 C)+10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{45045 b^4 d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}+\frac {4 a \left (a^2-b^2\right ) \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} F\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{45045 b^4 d \sqrt {a+b \cos (c+d x)}}-\frac {4 a \left (120 a^4 C+5 a^2 b^2 (143 A+94 C)-3 b^4 (2717 A+2174 C)\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{45045 b^3 d}-\frac {2 \left (240 a^4 C-539 b^4 (13 A+11 C)+10 a^2 b^2 (143 A+124 C)\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{45045 b^3 d}-\frac {4 a \left (143 A b^2+24 a^2 C+166 b^2 C\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{9009 b^3 d}+\frac {2 \left (24 a^2 C+11 b^2 (13 A+11 C)\right ) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{1287 b^3 d}-\frac {12 a C \cos (c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{143 b^2 d}+\frac {2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{7/2} \sin (c+d x)}{13 b d}\\ \end {align*}

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Mathematica [A]  time = 2.59, size = 395, normalized size = 0.76 \[ \frac {b (a+b \cos (c+d x)) \left (4 a \left (960 a^4 C+10 a^2 b^2 (572 A+331 C)+3 b^4 (71214 A+60793 C)\right ) \sin (c+d x)+b \left (5 b \left (2 a \left (60 a^2 C+10868 A b^2+13939 b^2 C\right ) \sin (3 (c+d x))+7 b \left (\left (636 a^2 C+572 A b^2+880 b^2 C\right ) \sin (4 (c+d x))+9 b C (54 a \sin (5 (c+d x))+11 b \sin (6 (c+d x)))\right )\right )+\left (-1440 a^4 C+120 a^2 b^2 (1430 A+1457 C)+77 b^4 (1976 A+1897 C)\right ) \sin (2 (c+d x))\right )\right )+32 \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \left (a b^2 \left (-60 a^4 C+5 a^2 b^2 (4433 A+3337 C)+3 b^4 (12441 A+10277 C)\right ) F\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )-\left (240 a^6 C+10 a^4 b^2 (143 A+76 C)-3 a^2 b^4 (13299 A+10223 C)-1617 b^6 (13 A+11 C)\right ) \left ((a+b) E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )-a F\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )\right )\right )}{720720 b^4 d \sqrt {a+b \cos (c+d x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^2*(a + b*Cos[c + d*x])^(5/2)*(A + C*Cos[c + d*x]^2),x]

[Out]

(32*Sqrt[(a + b*Cos[c + d*x])/(a + b)]*(a*b^2*(-60*a^4*C + 5*a^2*b^2*(4433*A + 3337*C) + 3*b^4*(12441*A + 1027
7*C))*EllipticF[(c + d*x)/2, (2*b)/(a + b)] - (240*a^6*C - 1617*b^6*(13*A + 11*C) + 10*a^4*b^2*(143*A + 76*C)
- 3*a^2*b^4*(13299*A + 10223*C))*((a + b)*EllipticE[(c + d*x)/2, (2*b)/(a + b)] - a*EllipticF[(c + d*x)/2, (2*
b)/(a + b)])) + b*(a + b*Cos[c + d*x])*(4*a*(960*a^4*C + 10*a^2*b^2*(572*A + 331*C) + 3*b^4*(71214*A + 60793*C
))*Sin[c + d*x] + b*((-1440*a^4*C + 120*a^2*b^2*(1430*A + 1457*C) + 77*b^4*(1976*A + 1897*C))*Sin[2*(c + d*x)]
+ 5*b*(2*a*(10868*A*b^2 + 60*a^2*C + 13939*b^2*C)*Sin[3*(c + d*x)] + 7*b*((572*A*b^2 + 636*a^2*C + 880*b^2*C)
*Sin[4*(c + d*x)] + 9*b*C*(54*a*Sin[5*(c + d*x)] + 11*b*Sin[6*(c + d*x)]))))))/(720720*b^4*d*Sqrt[a + b*Cos[c
+ d*x]])

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fricas [F]  time = 1.98, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (C b^{2} \cos \left (d x + c\right )^{6} + 2 \, C a b \cos \left (d x + c\right )^{5} + 2 \, A a b \cos \left (d x + c\right )^{3} + A a^{2} \cos \left (d x + c\right )^{2} + {\left (C a^{2} + A b^{2}\right )} \cos \left (d x + c\right )^{4}\right )} \sqrt {b \cos \left (d x + c\right ) + a}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="fricas")

[Out]

integral((C*b^2*cos(d*x + c)^6 + 2*C*a*b*cos(d*x + c)^5 + 2*A*a*b*cos(d*x + c)^3 + A*a^2*cos(d*x + c)^2 + (C*a
^2 + A*b^2)*cos(d*x + c)^4)*sqrt(b*cos(d*x + c) + a), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {5}{2}} \cos \left (d x + c\right )^{2}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="giac")

[Out]

integrate((C*cos(d*x + c)^2 + A)*(b*cos(d*x + c) + a)^(5/2)*cos(d*x + c)^2, x)

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maple [B]  time = 2.71, size = 2223, normalized size = 4.25 \[ \text {Expression too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x)

[Out]

-2/45045*((2*cos(1/2*d*x+1/2*c)^2*b+a-b)*sin(1/2*d*x+1/2*c)^2)^(1/2)*(30669*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2
*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^3*b^4-4435
20*C*b^7*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2*c)^14+(766080*C*a*b^6+1330560*C*b^7)*sin(1/2*d*x+1/2*c)^12*cos(1/2
*d*x+1/2*c)+(-160160*A*b^7-450240*C*a^2*b^5-1915200*C*a*b^6-1798720*C*b^7)*sin(1/2*d*x+1/2*c)^10*cos(1/2*d*x+1
/2*c)+(297440*A*a*b^6+320320*A*b^7+90240*C*a^3*b^4+900480*C*a^2*b^5+2159680*C*a*b^6+1379840*C*b^7)*sin(1/2*d*x
+1/2*c)^8*cos(1/2*d*x+1/2*c)+(-194480*A*a^2*b^5-446160*A*a*b^6-296296*A*b^7+120*C*a^4*b^3-135360*C*a^3*b^4-828
880*C*a^2*b^5-1324320*C*a*b^6-666512*C*b^7)*sin(1/2*d*x+1/2*c)^6*cos(1/2*d*x+1/2*c)+(45760*A*a^3*b^4+194480*A*
a^2*b^5+344344*A*a*b^6+136136*A*b^7+120*C*a^5*b^2-120*C*a^4*b^3+101840*C*a^3*b^4+378640*C*a^2*b^5+522368*C*a*b
^6+198352*C*b^7)*sin(1/2*d*x+1/2*c)^4*cos(1/2*d*x+1/2*c)+(-1430*A*a^4*b^3-22880*A*a^3*b^4-95238*A*a^2*b^5-9781
2*A*a*b^6-24024*A*b^7-240*C*a^6*b-60*C*a^5*b^2-760*C*a^4*b^3-28360*C*a^3*b^4-104466*C*a^2*b^5-104304*C*a*b^6-2
7258*C*b^7)*sin(1/2*d*x+1/2*c)^2*cos(1/2*d*x+1/2*c)-21021*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d
*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*b^7-17787*C*(sin(1/2*d*x+1/2*c
)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2)
)*b^7+240*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticF(cos(1/2
*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^7-240*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/
(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^7-17732*A*a^3*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2
*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*b^4-30669*C*
(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),
(-2*b/(a-b))^(1/2))*a^2*b^5-1430*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^
(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^5*b^2+16302*A*a*b^6*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*
b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))-39897*A*(sin(
1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b
/(a-b))^(1/2))*a^2*b^5+700*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*
EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^5*b^2+21021*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(
1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a*b^6-13984*C*a^3*(sin(1/
2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(
a-b))^(1/2))*b^4+13044*C*a*b^6*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2
)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))+240*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+
1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^6*b-760*C*(sin(1/2*d*x+1/2*c)^2
)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a
^5*b^2+17787*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(
1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a*b^6+1430*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+
(a+b)/(a-b))^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^5*b^2+39897*A*(sin(1/2*d*x+1/2*c)^2)^(1/
2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^3*b^
4+1430*A*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*EllipticE(cos(1/2*d*
x+1/2*c),(-2*b/(a-b))^(1/2))*a^4*b^3+760*C*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)
/(a-b))^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a^4*b^3)/b^4/(-2*sin(1/2*d*x+1/2*c)^4*b+(a+b)*s
in(1/2*d*x+1/2*c)^2)^(1/2)/sin(1/2*d*x+1/2*c)/(-2*sin(1/2*d*x+1/2*c)^2*b+a+b)^(1/2)/d

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (C \cos \left (d x + c\right )^{2} + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {5}{2}} \cos \left (d x + c\right )^{2}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^2*(a+b*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="maxima")

[Out]

integrate((C*cos(d*x + c)^2 + A)*(b*cos(d*x + c) + a)^(5/2)*cos(d*x + c)^2, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int {\cos \left (c+d\,x\right )}^2\,\left (C\,{\cos \left (c+d\,x\right )}^2+A\right )\,{\left (a+b\,\cos \left (c+d\,x\right )\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(c + d*x)^2*(A + C*cos(c + d*x)^2)*(a + b*cos(c + d*x))^(5/2),x)

[Out]

int(cos(c + d*x)^2*(A + C*cos(c + d*x)^2)*(a + b*cos(c + d*x))^(5/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**2*(a+b*cos(d*x+c))**(5/2)*(A+C*cos(d*x+c)**2),x)

[Out]

Timed out

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